y^2+4y-12=0

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Solution for y^2+4y-12=0 equation:


Simplifying
y2 + 4y + -12 = 0

Reorder the terms:
-12 + 4y + y2 = 0

Solving
-12 + 4y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-6 + -1y)(2 + -1y) = 0

Subproblem 1

Set the factor '(-6 + -1y)' equal to zero and attempt to solve: Simplifying -6 + -1y = 0 Solving -6 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + -1y = 0 + 6 Combine like terms: -6 + 6 = 0 0 + -1y = 0 + 6 -1y = 0 + 6 Combine like terms: 0 + 6 = 6 -1y = 6 Divide each side by '-1'. y = -6 Simplifying y = -6

Subproblem 2

Set the factor '(2 + -1y)' equal to zero and attempt to solve: Simplifying 2 + -1y = 0 Solving 2 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1y = 0 + -2 -1y = 0 + -2 Combine like terms: 0 + -2 = -2 -1y = -2 Divide each side by '-1'. y = 2 Simplifying y = 2

Solution

y = {-6, 2}

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